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a^2-27a-11=0
a = 1; b = -27; c = -11;
Δ = b2-4ac
Δ = -272-4·1·(-11)
Δ = 773
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-\sqrt{773}}{2*1}=\frac{27-\sqrt{773}}{2} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+\sqrt{773}}{2*1}=\frac{27+\sqrt{773}}{2} $
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